How create wrapper for callback?
javascript, jquery, jquery-forms-plugin
Solution
You're pretty close:
form.ajaxSubmit(wrapperCallBack(successCallback));
var wrapperCallBack = function (successCallback) {
return function() {
changeState(false);
return successCallback(this);
};
};
Or as I would prefer to write it:
form.ajaxSubmit(wrapperCallBack(successCallback));
function wrapperCallBack(successCallback) {
return function() {
changeState(false);
return successCallback(this);
};
}
There, `wrapperCallback` creates a function to wrap around its argument (the `successCallback` argument) and returns that function.
Both of those assume you're going to use `wrapperCallBack` to create wrappers more than once. If you only need a one-off, then you can just use an inline anonymous function:
form.ajaxSubmit(function() {
changeState(false);
return successCallback(this);
});
Problem
I use ajaxSubmit. ``` form.ajaxSubmit(successCallback); ``` I need create wrapper for successCallback. How to do this? I tried ``` form.ajaxSubmit(wrapperCallBack(successCallback)); var wrapperCallBack = function (successCallback) { debugger; changeState(false); successCallback(this); }; ```