Inheritance and templates in C++ - why are inherited members invisible?
c++, inheritance, templates
Solution
This is part of the rules concerning dependent names. `Method1` is not a dependent name in the scope of `Method2`. So the compiler doesn't look it up in dependent base classes.
There two ways to fix that: Using `this` or specifying the base type. More details on this very recent post or at the C++ FAQ. Also notice that you missed the public keyword and a semi-colon. Here's a fixed version of your code.
template <int a>
class Test {
public:
Test() {}
int MyMethod1() { return a; }
};
template <int b>
class Another : public Test<b>
{
public:
Another() {}
void MyMethod2() {
Test<b>::MyMethod1();
}
};
int main()
{
Another<5> a;
a.MyMethod1();
a.MyMethod2();
}
Problem
When a template publicly inherits from another template, aren't the base public methods supposed to be accessible? ``` template <int a> class Test { public: Test() {} int MyMethod1() { return a; } }; template <int b> class Another : public Test<b> { public: Another() {} void MyMethod2() { MyMethod1(); } }; int main() { Another<5> a; a.MyMethod1(); a.MyMethod2(); } ``` Well, GCC craps out on this... I must be missing something totally obvious (brain melt). Help?