Get the first lines of a Wikipedia article

Question

I got a Wikipedia article and I want to fetch the first z lines (or the first x characters, or the first y words; it doesn't matter) from the article. The problem: I can get either the source Wiki text (via the API) or the parsed HTML (via a direct HTTP request, eventually on the print-version), but how can I find the first lines displayed? Normally, the source (both HTML and wikitext) starts with the info-boxes and images and the first real text to display is somewhere down in the code. For example: Albert Einstein on Wikipedia (print version). Look in the code. The first real-text-line "Albert Einstein (pronounced /ˈælbərt ˈaɪnstaɪn/; German: [ˈalbɐt ˈaɪ̯nʃtaɪ̯n]; 14 March 1879–18 April 1955) was a theoretical physicist." is not on the start. The same applies to the Wiki source; it starts with the same info-box and so on. So how would you accomplish this task? The programming language is Java, but this shouldn't matter. A solution which came to my mind was to use an XPath query, but…

Accepted Answer

I worked out the following solution:

Using an XPath query on the XHTML source code (I took the print-version, because it is shorter, but it also works on the normal version).

```
//html/body//div[@id='bodyContent']/p[1]
```

This works on German and on English Wikipedia and I haven't found an article where it doesn't output the first paragraph. The solution is also quite fast, I also thought of only taking the first x characters of the XHTML, but this would render the XHTML invalid.

If someone is searching for the Java code, here it is then:

```
private static DocumentBuilderFactory dbf;

static {
    dbf = DocumentBuilderFactory.newInstance();
    dbf.setAttribute("http://apache.org/xml/features/nonvalidating/load-external-dtd", false);
}

private static XPathFactory xpathf = XPathFactory.newInstance();
private static String xexpr = "//html/body//div[@id='bodyContent']/p[1]";

private static String getPlainSummary(String url) {
    try {
        // Open Wikipage
        URL u = new URL(url);
        URLConnection uc = u.openConnection();
        uc.setRequestProperty("User-Agent", "Mozilla/5.0 (X11; U; Linux i686; en-US; rv:1.9.1) Gecko/20090616 Firefox/3.5");
        InputStream uio = uc.getInputStream();
        InputSource src = new InputSource(uio);

// Construct Builder
        DocumentBuilder builder = dbf.newDocumentBuilder();
        Document docXML = builder.parse(src);

// Apply XPath
        XPath xpath = xpathf.newXPath();
        XPathExpression xpathe = xpath.compile(xexpr);
        String s = xpathe.evaluate(docXML);

// Return Attribute
        if (s.length() == 0) {
            return null;
        } else {
            return s;
        }
    }
    catch (IOException ioe) {
        logger.error("Cant get XML", ioe);
        return null;
    }
    catch (ParserConfigurationException pce) {
        logger.error("Cant get DocumentBuilder", pce);
        return null;
    }
    catch (SAXException se) {
        logger.error("Cant parse XML", se);
        return null;
    }
    catch (XPathExpressionException xpee) {
        logger.error("Cant parse XPATH", xpee);
        return null;
    }
}
```

Use it by calling `getPlainSummary("http://de.wikipedia.org/wiki/Uma_Thurman");`

Get the first lines of a Wikipedia article

Solution

Problem