Java maximum literal number in eclipse
java
Solution
Those numbers are larger than the largest `int` value, which is 231-1 or 2147483647, and which is available as the constant `Integer.MAX_VALUE`.
The reason you were able to code it as `1000000000*10000` is because although each multiplicand is within the range of the maximum `int` value, the result is not and java handles this by overflowing the result so it falls within the valid range.
To fix the problem, make your variables `long` (64 bits) and your constants long also by appending `L` at the end if the number (the default numerical type in java is `int`), and your should use `Long.parseLong()` to cater for the larger values in your input.
Note that, like `int`, the range of `long` is limited too: to 263-1 or 9223372036854775807, which is available as the constant `Long.MAX_VALUE`.
For arbitrarily large numbers, use the `BigInteger` class.
Problem
I have a line that looks like ``` if(numb2 < 10000000000000 & numb2 > 100000000000){ ``` So in Eclipse it says 10000000000000 and 100000000000 are both out of the integer literal range. Specifically The literal 10000000000000 of type int is out of range and The literal 1000000000000 of type int is out of range I changed the line so it looked like ``` if(numb2 < 1000000000*10000 & numb2 > 100000000*1000){ ``` but if you typed a number in that range it just said ``` Exception in thread "main" java.lang.NumberFormatException: For input string: "5555555555555" at java.lang.NumberFormatException.forInputString(Unknown Source) at java.lang.Integer.parseInt(Unknown Source) at java.lang.Integer.parseInt(Unknown Source) at twothousandthirteen.LuckyNumber.main(LuckyNumber.java:12) ``` I would like to know if there is a way to extend the literal number range or do anything to fix the problem. Thanks KMehta