Order catch blocks when try to handle an exception

c#, exception, try-catch

Solution

From try-catch (C# Reference);

It is possible to use more than one specific catch clause in the same try-catch statement. In this case, the order of the catch clauses is important because the catch clauses are examined in order. Catch the more specific exceptions before the less specific ones. The compiler produces an error if you order your catch blocks so that a later block can never be reached.

You should use

try
{
    // throws IOException
}
catch(IOException e)
{
}
catch(Exception e)
{
}

Be aware, `Exception` class is the base class for all exceptions.

Problem

``` try { // throws IOException } catch(Exception e) { } catch(IOException e) { } ``` when `try` block throws `IOException`, it will call the first `catch` block, not the second one. Can anyone explain this? Why does it call the first `catch` block?

Original source