Replace NaN values in a list with zero (0)

nan, r

Solution

This is a perfect use case for `rapply`.

> rapply( z, f=function(x) ifelse(is.nan(x),0,x), how="replace" )
$a
[1] 1 2 3 0 5 8 0 0

$b
[1] 0 2 3 0 5 8 0 0

`lapply` would work too, but `rapply` deals properly with nested lists in this situation.

Problem

Hi dear I have a problem with `NaN`. I am working with a large dataset with many variables and they have `NaN`. The data is like this: ``` z=list(a=c(1,2,3,NaN,5,8,0,NaN),b=c(NaN,2,3,NaN,5,8,NaN,NaN)) ``` I used this commands to force the list to data frame but I got this: ``` z=as.data.frame(z) > is.list(z) [1] TRUE > is.data.frame(z) [1] TRUE > replace(z,is.nan(z),0) Error en is.nan(z) : default method not implemented for type 'list' ``` I forced z to data frame but it wasn't enough, maybe there is a form to change `NaN` in list. Thanks for your help. This data is only an example my original data has 36000 observations and 40 variables.

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