python: run a process with timeout and capture stdout, stderr and exit status
external-process, process, python
Solution
I hate doing the work by myself. Just copy this into your proc.py module.
import subprocess
import time
import sys
class Timeout(Exception):
pass
def run(command, timeout=10):
proc = subprocess.Popen(command, bufsize=0, stdout=subprocess.PIPE, stderr=subprocess.PIPE)
poll_seconds = .250
deadline = time.time()+timeout
while time.time() < deadline and proc.poll() == None:
time.sleep(poll_seconds)
if proc.poll() == None:
if float(sys.version[:3]) >= 2.6:
proc.terminate()
raise Timeout()
stdout, stderr = proc.communicate()
return stdout, stderr, proc.returncode
if __name__=="__main__":
print run(["ls", "-l"])
print run(["find", "/"], timeout=3) #should timeout
Problem
Possible Duplicate: subprocess with timeout What is the easiest way to do the following in Python: - Run an external process - Capture stdout in a string, stderr, and exit status - Set a timeout. I would like something like this: ``` import proc try: status, stdout, stderr = proc.run(["ls", "-l"], timeout=10) except proc.Timeout: print "failed" ```