Is there a function to do circular bitshift for a byte array in C#?

arrays, bit-manipulation, c#

Solution

This is not as simple as you'd think. Here's a quick version before this thread gets closed:

public static byte[] ROL_ByteArray(byte[] arr, int nShift)
{
    //Performs bitwise circular shift of 'arr' by 'nShift' bits to the left
    //RETURN:
    //      = Result
    byte[] resArr = new byte[arr.Length];

    if(arr.Length > 0)
    {
        int nByteShift = nShift / (sizeof(byte) * 8);   //Adjusted after @dasblinkenlight's correction
        int nBitShift = nShift % (sizeof(byte) * 8);

        if (nByteShift >= arr.Length)
            nByteShift %= arr.Length;

        int s = arr.Length - 1;
        int d = s - nByteShift;

        for (int nCnt = 0; nCnt < arr.Length; nCnt++, d--, s--)
        {
            while (d < 0)
                d += arr.Length;
            while (s < 0)
                s += arr.Length;

            byte byteS = arr[s];

            resArr[d] |= (byte)(byteS << nBitShift);
            resArr[d > 0 ? d - 1 : resArr.Length - 1] |= (byte)(byteS >> (sizeof(byte) * 8 - nBitShift));


        }
    }

    return resArr;
}

and here's a test:

byte[] arr = new byte[] {
    Convert.ToByte("11001110", 2),
    Convert.ToByte("01000100", 2),
    Convert.ToByte("10100001", 2),
    };

byte[] arr2 = Auth.ROL_ByteArray(arr, 1);

string sss = "";
for (int i = 0; i < arr2.Length; i++)
    sss += Convert.ToString(arr2[i], 2) + ", ";

Debug.WriteLine(sss);

Problem

I can't seem to find if there's a built-in way to do a circular bitshift of a byte array, what C's ROL and ROR used to do with a single byte? Let me explain, say, I have an array (in binary): ``` [0] = 11001110 [1] = 01000100 [2] = 10100001 ``` and then if I want to do `ROL_Array(1 bit)` or move bits 1 bit to the left, I'd get: ``` [0] = 10011100 [1] = 10001001 [2] = 01000011 ``` or, if I want to do `ROR_Array(2 bits)` or move bits 2 bits to the right, I'd get: ``` [0] = 00110011 [1] = 01010001 [2] = 10101000 ```

Original source

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