Java unsigned byte[2] to int?

Question

All I need to do is convert an unsigned two byte array to an integer. I know, I know, Java doesn't have unsigned data types, but my numbers are in pretend unsigned bytes. ``` byte[] b = {(byte)0x88, (byte)0xb8}; // aka 35000 int i = (byte)b[0] << 8 | (byte)b[1]; ``` Problem is that doesn't convert properly, because it thinks those are signed bytes... How do I convert it back to an int?

Accepted Answer

There are no unsigned numbers in Java, bytes or ints or anything else. When the bytes are converted to `int` prior to being bitshifted, they are sign-extended, i.e. `0x88` => `0xFFFFFF88`. You need to mask out what you don't need.

Try this

```
int i = ((b[0] << 8) & 0x0000ff00) | (b[1] & 0x000000ff);
```

and you will get 35000.

Java unsigned byte[2] to int?

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