Checking to see if a list is ordered consecutively

Question

Is there any library function in Haskell that'll allow me to check if a list is ordered consecutively? eg. [1,2,3,4] is valid, [1,2,3,10] is invalid. Basically I can have a list that ranges anywhere between 3 to 5 elements and I'm trying to check if that list is ordered consecutively. My Attempt (I'm not sure if this is the right way to approach it, seems to be way too much repetition) ``` isSucc:: [Integer] -> Bool isSucc[] = True isSucc(x:y:zs) = if (x+1) == y then True && isSucc(y:zs) else isSucc(y:zs) ``` After I have this function working, I'm planning on using it to filter a lists of lists (Keep the list inside the list only and only if it is ordered consecutively)

Accepted Answer

There's no standard function for that.

Here's a fixed version of your function, making it generic, removing the redundant conditions and adding the missing ones:

```
isSucc :: (Enum a, Eq a) => [a] -> Bool
isSucc [] = True
isSucc (x:[]) = True
isSucc (x:y:zs) | y == succ x = isSucc $ y:zs
isSucc _ = False
```

Checking to see if a list is ordered consecutively

Solution

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