Initialize pointer to structure - compiler warning
c++, c++11, g++, struct, warnings
Solution
Your `test` structure is an aggregate. While initialization of an aggregate with the braces syntax is supported in C++98, assignment is not.
Here, what is really going on is that the compiler invokes the implicitly generated move-assignment operator, which takes a `test&&` as its input. In order to make this call legal, the compiler will have to convert `{8, 55.2}` into an instance of `test` by constructing a temporary from it, then move-assign `*secondTest` from this temporary.
This behavior is supported only in C++11, which is why the compiler is telling you that you have to compile with the `-std=c++11` option.
Problem
``` #include <iostream> using namespace std; struct test { int factorX; double coefficient; }; int main() { test firstTest = {1, 7.5}; //that's ok test *secondTest = new test; *secondTest = {8, 55.2}; // issue a compiler warning } ``` I don't understand why the compiler issues the following warning: ``` test2.cpp:13:33: warning: extended initializer lists only available with -std=c++11 or -std=gnu++11 [enabled by default] test2.cpp:13:33: warning: extended initializer lists only available with -std=c++11 or -std=gnu++11 [enabled by default] ``` I know that in C++11 I can omit the assignment operator but that's not the case. I am using g++ 4.7.2.