Is it possible for a python function to ignore unused kwargs
keyword-argument, python
Solution
Sure. Just add `**kwargs` to the function signature:
def add(a, b, c, **kwargs):
return a + b + c
kwargs = dict(a=1, b=2, c=3, d=4)
print add(**kwargs)
#prints 6
Problem
If I have a simple function: ``` def add(a, b, c): return a + b + c ``` Is it possible for me to make it so that if I supply an unused kwarg, it is simply ignored? ``` kwargs = dict(a=1, b=2, c=3, d=4) print add(**kwargs) #prints 6 ```