how to generate a series representing the binary expansion of 'e'
algorithm, clojure, haskell, lazy-evaluation
Solution
Here's an unbounded spigot for `e` in Haskell:
main = print $ stream (1,0,1) [(n, a*d, d) | (n,d,a) <- map f [1..]]
where
f k = (1, k, 1)
stream z (x:xs)
| lbound == approx z 2 = lbound : stream (mul (10, -10*lbound, 1) z) (x:xs)
| otherwise = stream (mul z x) xs
where
lbound = approx z 1
approx (a,b,c) n = (a*n + b) `div` c
mul (a,b,c) (d,e,f) = (a*d, a*e + b*f, c*f)
Based on the Programming Praxis unbounded spigot for e and pi, which in turn is derived from Gibbon's first unbounded spigot for pi.
$ runhaskell A.hs
[2,7,1,8,2,8,1,8,2,8,4,5,9,0,4,5,2,3,5,3,6, ^C
I'd recommend Gibbon's paper if you're interested in these fun algorithms.
Problem
I'm trying to find the first 100,000 binary digits in the expansion of 'e'. Is there an algorithm to generate the binary digits of 'e' as a infinite list?