Python - Use 'set' to find the different items in list
compare, python
Solution
Looks like you need symmetric difference:
a = [1,2,3]
b = [3,4,5]
print(set(a)^set(b))
>>> [1,2,4,5]
Problem
I need to compare two lists in Python, and I know about using the `set` command to find similar items, but is there a another command I could use that would automatically compare them, instead of having to code for it? I would like to find the items that aren't in each one. Say list one is as follows: ``` [1, 2, 3, 4, 5, 6] ``` and list two is: ``` [1, 2, 3, 4, 6] ``` I want to find that `5` is missing from the list, hopefully by a command, but I do know how to loop through comparing.