How do I Get memberOf attribute from ldap DirContextOperations
java, ldap, spring, spring-ldap
Solution
You probably only miss one "s" from the end. Try:
ctx.getObjectAttributes("memberOf")
The javadoc clarifies what's the difference between the singular and plural form method. (The former only returns the first value even if the given attribute is multi-valued.)
Problem
I am tring to get a list of groups a user is a member of, currently I can get most attributes as follows ``` CustomLdapUserDetails.Essence essence = new CustomLdapUserDetails.Essence(); essence.setDn(dn); Object passwordValue = ctx.getObjectAttribute(passwordAttributeName); String givennameValue = (String)ctx.getObjectAttribute("givenname"); String snValue = (String)ctx.getObjectAttribute("sn"); String titleValue = (String)ctx.getObjectAttribute("title"); essence.setFirstname(givennameValue); essence.setLastname(snValue); ``` but I cannot figure out how to get the memberOf attribute. If I output the whole DirContextOperations as a String I get the following ``` org.springframework.ldap.core.DirContextAdapter: dn=uid=emp123 {rdn=uid=emp123, whenCreated=20110816063203.0Z, objectCategory=CN=fompanyPerson,CN=Schema,CN=Configuration,CN={9F17F445-56C4-42D9- B7C6-B630FFEA7F07}, badPwdCount=0, otherTelephone=123-456789, businessUnit=IREIRE BU, ntAccount=DMN1\emp123, managerID=emp987, objectGUID=5? ?e6A??????/, mail=emp123@somewhere.com, uid=emp123, companyWorkRelationship=EMP, memberOf[0]=CN=ABC IREIRE,OU=AutoGroups,DC=entdir,DC=gtn,DC=com, memberOf[1]=CN=azgEntJazzUsers,OU=AutoGroups,DC=entdir,DC=gtn,DC=com, companySite=DBL, companyCostCenter=91827, companyBusinessGroup=IREIRE BG, ntDomain=DMN1, instanceType=4, corpID=emp123, objectSid= I???&?C?k?J???????, st=XX, badPasswordTime=0, vdejoindn=P- ENTDIRXXX-1:uid=emp123,DC=entdirXXX,DC=gtn,DC=com, companySourceSystem=C-WORKSYSTEM, objectClass[0]=top, objectClass[1]=person, objectClass[2]=organizationalPerson, objectClass[3]=user, objectClass[4]=inetOrgPerson, objectClass[5]=fompanyPerson, company=ABC DEV, name=emp123, sn=Smith, exchangeAlias=emp123, telephoneNumber=1-987-6543, ntDomainRelative=DMN1, uSNChanged=999111, physicalDeliveryOfficeName=DXI, ntAccountRelative=DMN1\emp123, cn=Smith, John, exchangeServer=someServer, documentumUserName=Smith JOHN emp123, title=SOFTWARE ENGINEER/DEVELOPER, otherCertMailbox=emp123@xyz.somewhere.com, msDS-UserAccountDisabled=TRUE, managerName=Bloggs, Joe, givenName=John, uSNCreated=18418957, displayName=Smith, John, pwdLastSet=629579433359695509, fompanyPersonStatus=A, whenChanged=20120266070711.0Z, o=IREIRE BU, distinguishedName=uid=emp123,DC=entdirXXX,DC=gtn,DC=com, eDARevoke=N, division=SEF-GL , manager=uid=emp987,DC=entdirXXX,DC=gtn,DC=com, exchangeDirectory=SMXZG1DB, samAccountName=emp123, sametimeServer=cvxcluster} ``` What I need to get is the CN value of each memberOf into an array of Strings, I have tried: ``` ctx.getObjectAttribute("memberOf[1]")) ctx.getObjectAttribute("memberOf")) ctx.getObjectAttribute("memberOf=CN")) ``` I've seen examples online of setting but I could not find any examples of getting, is it really that much more complex then getting the other Attributes? Any advice would be greatly appreciated