How can type safety be guarded against implicit conversion in Java?

Question

Suppose a method is as following: ``` void foo(int i) { } ``` Is there a way to make the following call illegal or generate an exception? ``` foo((short)3); ```

Accepted Answer

Bruno's overloading will work, but if you are looking at preventing other types of casting, you can always box the integer into its Object class:

```
void foo(Integer i) {
    // handle data normally
}
```

This will prevent you from being able to send short arguments to it.

How can type safety be guarded against implicit conversion in Java?

Solution

Problem