Solving Quadratic Equation
python, python-2.7
Solution
This line is causing problems:
(-b+math.sqrt(b**2-4*a*c))/2*a
`x/2*a` is interpreted as `(x/2)*a`. You need more parentheses:
(-b + math.sqrt(b**2 - 4*a*c)) / (2 * a)
Also, if you're already storing `d`, why not use it?
x = (-b + math.sqrt(d)) / (2 * a)
Problem
My program doesn't seem to give me the right solutions. Sometimes it does, sometimes it doesn't. I can't find my error. Any Suggestions? ``` import math a,b,c = input("Enter the coefficients of a, b and c separated by commas: ") d = b**2-4*a*c # discriminant if d < 0: print "This equation has no real solution" elif d == 0: x = (-b+math.sqrt(b**2-4*a*c))/2*a print "This equation has one solutions: ", x else: x1 = (-b+math.sqrt(b**2-4*a*c))/2*a x2 = (-b-math.sqrt(b**2-4*a*c))/2*a print "This equation has two solutions: ", x1, " and", x2 ```