Pass a directory with argparse (no type checking needed)
argparse, python
Solution
Simply add:
parser.add_argument('directory',help='directory to use',action='store')
before your `args = parser.parse_args()` line. A simple test from the commandline shows that it does the right thing (printing `args` at the end of the script):
$ python test.py /foo/bar/baz
Namespace(directory='/foo/bar/baz', dump=False, fake=False, verbose=False)
$ python test.py
usage: test.py [-h] [-v] [-d] [-f] directory
test.py: error: too few arguments
Problem
I've written a file crawler and I'm trying to expand it. I want to use argparse to handle settings for the script including passing the starting directory in at the command line. Example: `/var/some/directory/` I have gotten several other arguments to work but I'm unable to pass this directory in correctly. I don't care if it's preceded by a flag or not, (e.g `-d /path/to/start/`) but I need to make sure that at the very least, this is argument is used as it will be the only mandatory option for the script to run. Code Sample: ``` parser = argparse.ArgumentParser(description='py pub crawler...') parser.add_argument('-v', '--verbose', help='verbose output from crawler', action="store_true") parser.add_argument('-d', '--dump', help='dumps and replaces existing dictionaries', action="store_true") parser.add_argument('-f', '--fake', help='crawl only, nothing stored to DB', action="store_true") args = parser.parse_args() if args.verbose: verbose = True if args.dump: dump = True if args.fake: fake = True ```