C++ partial method specialization
c++, partial-classes, templates
Solution
If you are already have specialized class you could give different implementation of `foo` in specialized class:
template<typename A, typename B>
class C
{
public:
void foo() { cout << "default" << endl; };
};
template<typename A>
class C<A, CObject>
{
public:
void foo() { cout << "CObject" << endl; };
};
To specialize member function in Visual C++ 2008 you could make it template too:
template<typename A, typename B>
class C
{
template<typename T>
void foo();
template<>
void foo<CObject>();
};
The solution above seems to will be available only in future C++ Standard (according to draft n2914 14.6.5.3/2).
Problem
Is there a partial specialization for template class method? ``` template <class A, class B> class C { void foo(); } ``` it doesn't work to specialize it like this: ``` template <class A> void C<A, CObject>::foo() {}; ``` Any help?