Store an integer value in a character array in C
c, char, int
Solution
You need to convert that number into a character. A cheap way to do it is:
sendBuffer[0] = '0' + count;
is there anyway to display integers greater than 9
If you need that you'll want to shift to more elaborate schemes. For example, if you want to convert an integer 42 into the string "42" you can say:
#define ENOUGH ((CHAR_BIT * sizeof(int) - 1) / 3 + 2)
char str[ENOUGH];
snprint(str, sizeof str, "%d", 42);
Credit for `ENOUGH` goes to caf.
Problem
It is a very trivial question but I don't know why I am not getting the correct output. Here is what I am trying to do: ``` char sendBuffer[1000]; int count=0: while(count<10) { sendBuffer[0]=count; sendBuffer[1]='a'; sendBuffer[2]='b'; sendBuffer[3]='c'; sendBuffer[4]='\0'; printf(%s,sendBuffer); count=count+1; } ``` In the output, all buffer is printed correctly except the first index. I want 1,2,3 and so on to be printed at the start of the buffer but it does not work. Please Help