Bash variable from command with pipes, quotes, etc

bash, pipe, variables

Solution

VAR=$( dig axfr @dc1.localdomain.com localdomain.com |
     grep -i Lawler |
     awk '{ getline ; $1=substr($1,1,length($1)-1); print $1 ; exit }' )

Problem

I have a command I'm using to get the hostname.localdomain: ``` dig axfr @dc1.localdomain.com localdomain.com | grep -i Lawler | awk '{ getline ; $1=substr($1,1,length($1)-1); print $1 ; exit }' ``` This nicely returns a result like: michael.lawler.localdomain.com I'd like to further use that result as a variable in a Bash script. It seems I'm having trouble getting past the first pipe. If I `VAR="dig axfr @dc1.localdomain.com localdomain.com | grep -i Lawler | awk '{ getline ; $1=substr($1,1,length($1)-1); print $1 ; exit }'"` ...I get back the entire zone transfer. I've also tried many minor changes, adding `$` before the `dig` command, without quotes, but nothing seems to work. How can I fix this?

Original source

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