Python bitand (&) vs and

bitwise-operators, logical-and, python

Solution

You got confused with the operators; `and` is the correct boolean test, `&` is a binary bitwise operator instead:

if opg == 160 and opc == 129:

As a numeric operator, the `&` operator has a higher precedence than comparison operators, while the boolean operators have a lower precedence. The expression `opg == 160 & opc == 129` is thus interpreted as `opg == (160 & opc) == 129` instead, which is probably not what you wanted.

You can simplify your code somewhat:

for line in response.body.splitlines():
    if line:
        line = map(int, line.split())
        opg, opc, value = line[2], line[3], line[5]
        if opg == 160 and opc == 129:
            ret['success'] = "valore: %s" % (value)
            self.write(tornado.escape.json_encode(ret))

Problem

Hi all I have this part of code: ``` for line in response.body.split("\n"): if line != "": opg = int(line.split(" ")[2]) opc = int(line.split(" ")[3]) value = int(line.split(" ")[5]) if opg==160 & opc==129: ret['success'] = "valore: %s" % (value) self.write(tornado.escape.json_encode(ret)) ``` I have a series of line of type ``` 1362581670 2459546910990453036 156 0 30 0 ``` I want to take only the line where the third and fourth element is respectively 160 and 129. This code doesn't work. Do I have to do some casting? I think opg==160 is working to compare int with int...

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