awk and printf in bash
awk, bash, printf
Solution
The 5th comma-separated field from the uptime output is non-existant (on my system at least), which is why you keep getting zero. The 5-minute uptime is the second-to-last field, so this works:
uptime | awk '{printf "%.0f\n",$(NF-1)}'
Problem
I am trying to get the rounded number of the average load in the past 5 mins. So here goes my command: ``` uptime | awk -F, '{print $5}'|printf "%.0f\n" ``` It seems incorrect as it always give me 0. If I tried to use a variable as intermediate between awk and printf, then it is correct ``` avgload=$(uptime | awk -F, '{print $5}') printf "%.0f\n" $avgload ``` So anything wrong with my first try? Thanks and regards! UPDATE: Just for getting the average load in the past 5 mins, here is the output of uptime on my linux server (Kubuntu) `$ uptime 13:52:19 up 29 days, 18 min, 15 users, load average: 10.02, 10.04, 9.58` On my laptop (Ubuntu) it is similar `$ uptime 13:53:58 up 3 days, 12:02, 8 users, load average: 0.29, 0.48, 0.60 ` That's why I take the 5th field.