Min and max in multidimensional array
arrays, javascript
Solution
You had the right idea with `.apply` but you need to pass a collection of the `x` values.
var xVals = a.map(function(obj) { return obj.x; });
var min = Math.min.apply(null, xVals);
The `.map()` method makes a new Array comprised of whatever you returned in each iteration.
[10, 20, 30, 10]
Then passing the Array as the second argument to `.apply` will distribute the members of the Array as individual arguments. So it's as though you did this:
Math.min(10, 20, 30, 10) // 10
But since you need to `.map()`, you might as well skip the `Math.min`, and just use `.reduce` instead.
var min = a.reduce(function(min, obj) {
return obj.x < min ? obj.x : min;
}, Infinity);
Problem
My array is: ``` var a = new Array(); a[0] = {x: 10,y: 10}; a[1] = {x: 20,y: 50}; a[2] = {x: 30,y: 20}; a[3] = {x: 10,y: 10}; ``` `var min = Math.min.apply(null, a.x)` doesn't work. Some ideas?