Finding intersection/difference between python lists
list, numpy, python
Solution
A list comprehension will work.
a = [('when', 3), ('why', 4), ('throw', 9), ('send', 15), ('you', 1)]
b = ['the', 'when', 'send', 'we', 'us']
filtered = [i for i in a if not i[0] in b]
>>>print(filtered)
[('why', 4), ('throw', 9), ('you', 1)]
Problem
I have two python lists: ``` a = [('when', 3), ('why', 4), ('throw', 9), ('send', 15), ('you', 1)] b = ['the', 'when', 'send', 'we', 'us'] ``` I need to filter out all the elements from a that are similar to those in b. Like in this case, I should get: ``` c = [('why', 4), ('throw', 9), ('you', 1)] ``` What should be the most effective way?