Best way to split a hexadecimal?
hex, python
Solution
This returns the high byte and the low byte as a tuple:
def bytes(integer):
return divmod(integer, 0x100)
For example:
>>> high, low = bytes(0x607F)
>>> hex(high)
'0x60'
>>> hex(low)
'0x7f'
BTW, depending on what you need the bytes for, and where the integer came from, there might be much better ways to do what you need.
Problem
I'm pretty new to hexadecimal in general, and I've got an application that needs me to split a hexadecimal number. For example, given the number 0x607F, I would need to return the high (0x60) or low (0x7F) byte. This is may implementation, it feels a little cloogy though. Is there a more standard way to do this in python? ``` def byte(integer,highlow): assert highlow=='high' or highlow=='low' if highlow=='high': return hex(int(bin(integer)[:-8],2)) if highlow=='low': return hex(int(bin(integer)[-8:],2)) ```