Get the directory path of absolute file path in Python

path, python

Solution

You are looking for this:

>>> import os.path
>>> fullpath = '/absolute/path/to/file'
>>> os.path.dirname(fullpath)
'/absolute/path/to'

Related functions:

>>> os.path.basename(fullpath)
'file'
>>> os.path.split(fullpath)
('/absolute/path/to','file')

Problem

I want to get the directory where the file resides. For example the full path is: ``` fullpath = "/absolute/path/to/file" # something like: os.getdir(fullpath) # if this existed and behaved like I wanted, it would return "/absolute/path/to" ``` I could do it like this: ``` dir = '/'.join(fullpath.split('/')[:-1]) ``` But the example above relies on specific directory separator and is not really pretty. Is there a better way?

Original source