How to create a new System.Xml.Linq.XElement with PowerShell
powershell, system.xml, xml
Solution
"XName does not contain any public constructors. Instead, this class provides an implicit conversion from String that allows you to create an XName."
Base on this you can cast `String` to `XName`:
$xname = [System.Xml.Linq.XName]"foo"
$xname.GetType()
IsPublic IsSerial Name BaseType
-------- -------- ---- --------
True True XName System.Object
then:
$el = new-Object System.Xml.Linq.XElement $xname
$el
FirstAttribute :
HasAttributes : False
HasElements : False
IsEmpty : True
LastAttribute :
Name : foo
NodeType : Element
Value :
FirstNode :
LastNode :
NextNode :
PreviousNode :
BaseUri :
Document :
Parent :
LineNumber : 0
LinePosition : 0
Problem
I want to create an XML DOM programmatically using the System.Xml.Linq objects. I'd rather not parse a string or load a file from disk to create the DOM. In C# this is easy enough, but trying to do this in PowerShell does not seem possible. Option 1: Doesn't work ``` $xlinq = [Reflection.Assembly]::Load("System.Xml.Linq, Version=3.5.0.0, Culture=neutral, PublicKeyToken=b77a5c561934e089") $el = new-Object System.Xml.Linq.XElement "foo" ``` This gives the following error: ``` new-Object : Cannot convert argument "0", with value: "foo", for "XElement" to type "System.Xml.Linq.XElement": "Cannot convert value "foo" to type "System.Xml.Linq.XElement". Error: "Data at the root level is invalid. Line 1, position 1."" ``` Option 2: Doesn't work ``` $xlinq = [Reflection.Assembly]::Load("System.Xml.Linq, Version=3.5.0.0, Culture=neutral, PublicKeyToken=b77a5c561934e089") $xname = New-Object System.Xml.Linq.XName "foo" $el = new-Object System.Xml.Linq.XElement $xname ``` It gives this error: ``` New-Object : Constructor not found. Cannot find an appropriate constructor for type System.Xml.Linq.XName. ``` According to MSDN (http://msdn.microsoft.com/en-us/library/system.xml.linq.xname.aspx) "XName does not contain any public constructors. Instead, this class provides an implicit conversion from String that allows you to create an XName."