How can I check if two strings are anagrams of each other?
anagram, python
Solution
You need to think through your conditional logic a bit more. The loop is on the right track, but if there is a letter in s1 that is NOT in s2, you should `break` out of this loop and print the "False" statement. Consider using a variable like `all_s1_in_s2 = True` and then setting that to false if you find a letter that doesn't match.
Some other tips:
`for l in s1` will loop through string s1 giving you access to each letter in sequence as `l` - you don't need `range` or `len` at all
The `if .. in` statement can help test whether a letter exists in a string, e.g. `if letter in mystring:` is a valid statement and this could help you a lot, again not needing `range` or `len`
You should avoid using numbers in variable names where possible - better would be `word_one` and `word_two`, as an example
Problem
I am trying to write a program that accepts two strings from the user: ``` s1 = input("Please enter a word:") s2 = input("Please enter another word:") ``` How can I output `True` if the two are anagrams and `False` otherwise? If you found this question from a search engine and want to look for possibly multiple anagrams within a list: it is possible, but not optimal to compare each pair of elements. Please see Using Python, find anagrams for a list of words for more specific advice.