How to remove escape sequence like '\xe2' or '\x0c' in python
escaping, python, regex, string-literals
Solution
The problem is that `\xXX` is just a representation of a control character, not the character itself. Therefore, you can't literally match `\x` unless you're working with the `repr` of the string.
You can remove nonprintable characters using a character class:
re.sub(r'[\x00-\x08\x0b\x0c\x0e-\x1f\x7f-\xff]', '', text)
Example:
>>> re.sub(r'[\x00-\x1f\x7f-\xff]', '', ''.join(map(chr, range(256))))
' !"#$%&\'()*+,-./0123456789:;<=>?@ABCDEFGHIJKLMNOPQRSTUVWXYZ[\\]^_`abcdefghijklmnopqrstuvwxyz{|}~'
Problem
I am working on a project (content based search), for that I am using 'pdftotext' command line utility in Ubuntu which writes all the text from pdf to some text file. But it also writes bullets, now when I'm reading the file to index each word, it also gets some escape sequence indexed(like '\x01').I know its because of bullets(•). I want only text, so is there any way to remove this escape sequence.I have done something like this ``` escape_char = re.compile('\+x[0123456789abcdef]*') re.sub(escape_char, " ", string) ``` But this do not remove escape sequence Thanks in advance.