Change XML tag name

groovy, xmlslurper

Solution

Adding the 'magic' in to the code in the question gives:

def xml = """<tag id="root">
            |  <tag id="foo" other="blah" more="meh">
            |    <tag id="bar" other="huh"/>
            |  </tag>
            |</tag>""".stripMargin()

def root = new XmlSlurper().parseText(xml)

root.breadthFirst().each { n ->
  n.replaceNode { 
    "${n.@id}"( n.children() )
  }
}

println groovy.xml.XmlUtil.serialize(root)

Which prints:

<?xml version="1.0" encoding="UTF-8"?><root>
  <foo>
    <bar/>
  </foo>
</root>

HOWEVER, this will drop any content in the nodes. To maintain content, we would probably need to use recursion and XmlParser to generate a new doc from the existing one... I'll have a think

More general solution

I think this is more generalised:

import groovy.xml.*

def xml = """<tag id="root">
            |  <tag id="foo" other="blah" more="meh">
            |    <tag id="bar" other="huh">
            |      something
            |    </tag>
            |    <tag id="bar" other="huh">
            |      something else
            |    </tag>
            |    <noid>woo</noid>
            |  </tag>
            |</tag>""".stripMargin()

def root = new XmlParser().parseText( xml )

def munge( builder, node ) {
  if( node instanceof Node && node.children() ) {
    builder."${node.@id ?: node.name()}" {
      node.children().each {
        munge( builder, it )
      }
    }
  }
  else {
    if( node instanceof Node ) {
      "${node.@id ?: node.name()}"()
    }
    else {
      builder.mkp.yield node
    }
  }
}

def w = new StringWriter()
def builder = new MarkupBuilder( w )
munge( builder, root )

println XmlUtil.serialize( w.toString() )

And prints:

<?xml version="1.0" encoding="UTF-8"?><root>
  <foo>
    <bar>something</bar>
    <bar>something else</bar>
    <noid>woo</noid>
  </foo>
</root>

Now passes through nodes with no (or empty) `id` attributes

Problem

I want to transform an XML document which I have parsed with `XmlSlurper`. The (identical) XML tag names should be replaced with the value of the `id` attribute; all other attributes should be dropped. Starting from this code: ``` def xml = """<tag id="root"> | <tag id="foo" other="blah" more="meh"> | <tag id="bar" other="huh"/> | </tag> |</tag>""".stripMargin() def root = new XmlSlurper().parseText(xml) // Some magic here. println groovy.xml.XmlUtil.serialize(root) ``` I want to get the following: ``` <root> <foo> <bar/> </foo> </root> ``` (I write test assertions on the XML, and want to simplify the structure for them.) I've read Updating XML with XmlSlurper and searched around, but found no way with `replaceNode()` or `replaceBody()` to exchange a node while keeping its children.

Original source