Bash script and rows

Question

my problem is with rows mysql_query. I need: ``` Record 0: 2,text is text,3.23 ``` But I have: ``` Record 0: 2 Record 1: text Record 2: is Record 3: text Record 4: 3.23 ``` Please help me. ``` results=($(mysql --user root -proot test -Bse "select id,name from Object")); cnt=${#results[@]} for (( i=0 ; i<${cnt} ; i++ )) do echo "Record No. $i: ${results[$i]}" fieldA=${results[0]}; fieldB=${results[1]}; done ```

Accepted Answer

The problem is that you are storing the output of `mysql` into an array. Now, if `mysql` returns multiple records you won't know when a record ends and the next one starts because the array will contain the "flattened" data e.g. `( record1_fieldA record1_fieldB record2_fieldA record2_fieldB ... )`

Instead, use a `while` loop to iterate over the records like this:

```
i=0
while read fieldA fieldB
do
    echo "Record $(( i++ )): fieldA: $fieldA fieldB: $fieldB"
done < <(mysql --user root -proot test -Bse "select id,name from Object")
```

Bash script and rows

Solution

Problem