is that char null terminator is including in the length count

Question

``` #include <stdio.h> int main(int argc, char *argv[]) { char s[]="help"; printf("%d",strlen(s)); } ``` Why the above output is 4, isnt that 5 is the correct answer? it should be 'h','e','l','p','\0' in memory.. Thanks.

Accepted Answer

`strlen`: Returns the length of the given byte string not including null terminator;

```
char s[]="help";
strlen(s) should return 4.
```

`sizeof`: Returns the length of the given byte string, include null terminator;

```
char s[]="help";
sizeof(s) should return 5.
```

is that char null terminator is including in the length count

Solution

Problem