Can I fold with an infix operator without writing out an anonymous function?

Question

If I wanted to add up a list I could do this: ``` - List.foldr (fn (x, y) => x + y) 0 [1, 2, 3] val it = 6 : int ``` Is there any way to write something more along the lines of: ``` List.foldr + 0 [1, 2, 3] ``` I tried something like this: ``` fun inf2f op = fn (x, y) => x op y; ```

Accepted Answer

You're close. Add the `op` keyword in the second example.

```
- List.foldr op + 0 [1,2,3];
val it = 6 : int
```

Can I fold with an infix operator without writing out an anonymous function?

Solution

Problem