Line break when no data in ggplot2

datetime, ggplot2, posixct, r

Solution

You'll have to set `group` by setting a common value to those points you'd like to be connected. Here, you can set the first 4 values to say `1` and the last 2 to `2`. And keep them as factors. That is,

df1$grp <- factor(rep(1:2, c(4,2)))
g <- ggplot(df1, aes(x=Date, y=Counts)) + geom_line(aes(group = grp)) + 
                     geom_point()

Edit: Once you have your `data.frame` loaded, you can use this code to automatically generate the `grp` column:

idx <- c(1, diff(df$Date))
i2 <- c(1,which(idx != 1), nrow(df)+1)
df1$grp <- rep(1:length(diff(i2)), diff(i2))

Note: It is important to add `geom_point()` as well because if the `discontinuous range` happens to be the LAST entry in the data.frame, it won't be plotted (as there are not 2 points to connect the line). In this case, `geom_point()` will plot it.

As an example, I'll generate a data with more gaps:

# get a test data
set.seed(1234)
df <- data.frame(Date=seq(as.POSIXct("05:00", format="%H:%M"), 
                as.POSIXct("23:00", format="%H:%M"), by="hours"))
df$Counts <- sample(19)
df <- df[-c(4,7,17,18),]

# generate the groups automatically and plot
idx <- c(1, diff(df$Date))
i2 <- c(1,which(idx != 1), nrow(df)+1)
df$grp <- rep(1:length(diff(i2)), diff(i2))
g <- ggplot(df, aes(x=Date, y=Counts)) + geom_line(aes(group = grp)) + 
            geom_point()
g

Edit: For your NEW data (assuming it is `df`),

df$t <- strptime(paste(df$Date, df$Time), format="%d/%m/%Y %H:%M:%S")

idx <- c(10, diff(df$t))
i2 <- c(1,which(idx != 10), nrow(df)+1)
df$grp <- rep(1:length(diff(i2)), diff(i2))

now plot with `aes(x=t, ...)`.

Problem

I am using R to plot some data. ``` Date <- c("07/12/2012 05:00:00", "07/12/2012 06:00:00", "07/12/2012 07:00:00", "07/12/2012 08:00:00","07/12/2012 10:00:00","07/12/2012 11:00:00") Date <- strptime(Date, "%d/%m/%Y %H:%M") Counts <- c("0","3","10","6","5","4") Counts <- as.numeric(Counts) df1 <- data.frame(Date,Counts,stringsAsFactors = FALSE) library(ggplot2) g = ggplot(df1, aes(x=Date, y=Counts)) + geom_line(aes(group = 1)) g ``` How do I ask R not to plot data as a continuous line when there is a break in time? I normally have a data point every hour, but sometimes there is a break (between 8 am and 10 am). Between these points, I don't want the line to connect. Is this possible in R? Edit Many thanks for the responses here. My data is now in 10 second intervals, and I wish to do the same piece of analysis using this data. ``` df <- structure(list(Date = c("11/12/2012", "11/12/2012", "11/12/2012", "11/12/2012", "11/12/2012", "11/12/2012", "11/12/2012", "11/12/2012", "11/12/2012", "11/12/2012", "11/12/2012"), Time = c("20:16:00", "20:16:10", "20:16:20", "20:16:30", "20:16:40", "20:16:50", "20:43:30", "20:43:40", "20:43:50", "20:44:00", "20:44:10"), Axis1 = c(181L, 14L, 65L, 79L, 137L, 104L, 7L, 0L, 0L, 14L, 0L), Steps = c(13L, 1L, 6L, 3L, 8L, 4L, 1L, 0L, 0L, 0L, 0L)), .Names = c("Date", "Time", "Axis1", "Steps"), row.names = c(57337L, 57338L, 57339L, 57340L, 57341L, 57342L, 57502L, 57503L, 57504L, 57505L, 57506L), class = "data.frame") ``` I think I understand what the code is trying to do, when it adds the column 'group' to the original dataframe, but my question surrounds how I get R to know the data is now in 10 second intervals? When I apply the first line of code to determine whether the numbers are continuous or whether there is a gap (e.g. idx <- c(1, diff(df$Time)), I get the following error: ``` Error in r[i1] - r[-length(r):-(length(r) - lag + 1L)] : non-numeric argument to binary operator ``` After my `Time` variable, do I need to add `as.POSIXct` to ensure it recognises the time correctly?

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