Can I use GCC's __builtin_expect() with ternary operator in C
branch-prediction, c, gcc, ternary-operator
Solution
It apparently works for both ternary and regular if statements.
First, let's take a look at the following three code samples, two of which use `__builtin_expect` in both regular-if and ternary-if styles, and a third which does not use it at all.
builtin.c:
int main()
{
char c = getchar();
const char *printVal;
if (__builtin_expect(c == 'c', 1))
{
printVal = "Took expected branch!\n";
}
else
{
printVal = "Boo!\n";
}
printf(printVal);
}
ternary.c:
int main()
{
char c = getchar();
const char *printVal = __builtin_expect(c == 'c', 1)
? "Took expected branch!\n"
: "Boo!\n";
printf(printVal);
}
nobuiltin.c:
int main()
{
char c = getchar();
const char *printVal;
if (c == 'c')
{
printVal = "Took expected branch!\n";
}
else
{
printVal = "Boo!\n";
}
printf(printVal);
}
When compiled with `-O3`, all three result in the same assembly. However, when the `-O` is left out (on GCC 4.7.2), both ternary.c and builtin.c have the same assembly listing (where it matters):
builtin.s:
.file "builtin.c"
.section .rodata
.LC0:
.string "Took expected branch!\n"
.LC1:
.string "Boo!\n"
.text
.globl main
.type main, @function
main:
.LFB0:
.cfi_startproc
pushl %ebp
.cfi_def_cfa_offset 8
.cfi_offset 5, -8
movl %esp, %ebp
.cfi_def_cfa_register 5
andl $-16, %esp
subl $32, %esp
call getchar
movb %al, 27(%esp)
cmpb $99, 27(%esp)
sete %al
movzbl %al, %eax
testl %eax, %eax
je .L2
movl $.LC0, 28(%esp)
jmp .L3
.L2:
movl $.LC1, 28(%esp)
.L3:
movl 28(%esp), %eax
movl %eax, (%esp)
call printf
leave
.cfi_restore 5
.cfi_def_cfa 4, 4
ret
.cfi_endproc
.LFE0:
.size main, .-main
.ident "GCC: (Debian 4.7.2-4) 4.7.2"
.section .note.GNU-stack,"",@progbits
ternary.s:
.file "ternary.c"
.section .rodata
.LC0:
.string "Took expected branch!\n"
.LC1:
.string "Boo!\n"
.text
.globl main
.type main, @function
main:
.LFB0:
.cfi_startproc
pushl %ebp
.cfi_def_cfa_offset 8
.cfi_offset 5, -8
movl %esp, %ebp
.cfi_def_cfa_register 5
andl $-16, %esp
subl $32, %esp
call getchar
movb %al, 31(%esp)
cmpb $99, 31(%esp)
sete %al
movzbl %al, %eax
testl %eax, %eax
je .L2
movl $.LC0, %eax
jmp .L3
.L2:
movl $.LC1, %eax
.L3:
movl %eax, 24(%esp)
movl 24(%esp), %eax
movl %eax, (%esp)
call printf
leave
.cfi_restore 5
.cfi_def_cfa 4, 4
ret
.cfi_endproc
.LFE0:
.size main, .-main
.ident "GCC: (Debian 4.7.2-4) 4.7.2"
.section .note.GNU-stack,"",@progbits
Whereas nobuiltin.c does not:
.file "nobuiltin.c"
.section .rodata
.LC0:
.string "Took expected branch!\n"
.LC1:
.string "Boo!\n"
.text
.globl main
.type main, @function
main:
.LFB0:
.cfi_startproc
pushl %ebp
.cfi_def_cfa_offset 8
.cfi_offset 5, -8
movl %esp, %ebp
.cfi_def_cfa_register 5
andl $-16, %esp
subl $32, %esp
call getchar
movb %al, 27(%esp)
cmpb $99, 27(%esp)
jne .L2
movl $.LC0, 28(%esp)
jmp .L3
.L2:
movl $.LC1, 28(%esp)
.L3:
movl 28(%esp), %eax
movl %eax, (%esp)
call printf
leave
.cfi_restore 5
.cfi_def_cfa 4, 4
ret
.cfi_endproc
.LFE0:
.size main, .-main
.ident "GCC: (Debian 4.7.2-4) 4.7.2"
.section .note.GNU-stack,"",@progbits
The relevant part:
Basically, `__builtin_expect` causes extra code (`sete %al`...) to be executed before the `je .L2` based on the outcome of `testl %eax, %eax` which the CPU is more likely to predict as being 1 (naive assumption, here) instead of based on the direct comparison of the input char with `'c'`. Whereas in the nobuiltin.c case, no such code exists and the `je`/`jne` directly follows the comparison with 'c' (`cmp $99`). Remember, branch prediction is mainly done in the CPU, and here GCC is simply "laying a trap" for the CPU branch predictor to assume which path will be taken (via the extra code and the switching of `je` and `jne`, though I do not have a source for this, as Intel's official optimization manual does not mention treating first-encounters with `je` vs `jne` differently for branch prediction! I can only assume the GCC team arrived at this via trial and error).
I am sure there are better test cases where GCC's branch prediction can be seen more directly (instead of observing hints to the CPU), though I do not know how to emulate such a case succinctly/concisely. (Guess: it would likely involve loop unrolling during compilation.)
Problem
The GCC manual only shows examples where __builtin_expect() is placed around the entire condition of an 'if' statement. I also noticed that GCC does not complain if I use it, for example, with a ternary operator, or in any arbitrary integral expression for that matter, even one that is not used in a branching context. So, I wonder what the underlying constraints of its usage actually are. Will it retain its effect when used in a ternary operation like this: ``` int foo(int i) { return __builtin_expect(i == 7, 1) ? 100 : 200; } ``` And what about this case: ``` int foo(int i) { return __builtin_expect(i, 7) == 7 ? 100 : 200; } ``` And this one: ``` int foo(int i) { int j = __builtin_expect(i, 7); return j == 7 ? 100 : 200; } ```