Is it possible to make an object expose the interface of an type parameter?

c#, design-patterns, generics, oop

Solution

This isn't possible.

In my opinion, I don't think that a wrapper should be implemented using inheritance.

For example, let's say we've an `Engine` class and you need to implement a `FerrariEngine`. And you have a `Car` class.

You're saying that `Car` should inherit `FerrariEngine`. It looks terrible for me!

At the end of the day, you're looking to do something like dependency injection using inheritance and, again, this isn't the right path.

My suggestion is don't try to make your life easier: decide an architecture based on rational points.

UPDATE

The OP said in some comment:

I want to make this class to manage instances of objects of type T, so that the client does not need to take care of when the instances need to be created.

You don't need to make strange things to get what you want:

public interface IEngine 
{
     void Start();
}

public sealed class FerrariEngine : IEngine
{
     public FerrariEngine()
     {
          Start();
     }

     public void Start()
     {
     }
}

public abstract class Car<TEngine> where TEngine: IEngine, new()
{
    public Car()
    {
        _engine = new Lazy<TEngine>(() => new TEngine());
    }

    private readonly Lazy<TEngine> _engine;

    public TEngine Engine
    {
        get { return _engine.Value; }
    }
}

public class FerrariCar : Car<FerrariEngine>
{
}

Finally, if we create an instance of `FerrariCar`:

Car<FerrariEngine> myFerrari = new FerrariCar();

The engine will be instantiated and started, without developer intervention!

Check how `Lazy<T>` and basic generic constraints make the job ;)

In summary:

- Using `Lazy<T>` the engine will be instantiated only when some access the `Engine` property.

- Once the lazy-loaded engine is instantiated, since `FerrariEngine` implements a parameterless constructor calling `Start()` itself, it will start the engine.

I believe that this sample illustrates you how you can get what you're looking for and using C# "as is"!

Problem

In C#, is it possible to write something like this: ``` public class MyClass<T> : T where T : class, new() { } ``` I know that the above implementation does not compile, but what I am actually trying to achive is implementing some kind of generic wrapper to an unknown type, so that an client can call the wrapper just as he would call the type, provided by the parameter `T`, instead of calling it using something like `wrapper.Instance.SomeMember()`. Thanks in advance!

Original source

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