Can I send an operator as parameter to a function?
c++
Solution
Unfortunately, that’s not possible. There are wrappers for some common operators in the C++ standard library, in the `functional` header, e.g. `std::plus<T>`. It won’t work with your code though, since your `print` function requires a specific function parameter which `plus<int>` isn’t.
Instead of that, try passing a template argument, that works much better:
template <typename BinaryFunction>
void print(int a, int b, BinaryFunction f);
print(12, 13, std::plus<int>());
Problem
For example I can write in c: ``` int sum(int a, int b); void print(int a, int b, int (*f)(int, int)); ``` The question is can I send an operator? ``` print(12, 13, sum); // print(12, 13, operator +); compilation error ```