Creating a sequence starting with 0
r, seq
Solution
As others have said you want `0:14` or `seq(from=0,to=14)` The reason you get your undesired result is also worth noting.
In this case, the colon operator on its own (as described in `?':'`) is generating the desired regular sequence of integers, which you are then supplying to `seq()`.
`seq()` is guessing that you mean `seq(along.with = 0:14)` which returns a sequence of the same length as the thing you supplied. And of course it is using the default `from = 1`. So it gives you a sequence of fifteen integers starting at one. It's roughly analogous to this:
(x <- 0:14)
# [1] 0 1 2 3 4 5 6 7 8 9 10 11 12 13 14
seq(along.with = x, from = 1)
# [1] 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15
Despite causing the error you got, this `along.with` functionality is clearly useful for making sequences that are the same length as some vector/list/matrix:
seq(c(1,"w",5,6,NA))
# [1] 1 2 3 4 5
And we can't say `?seq` didn't warn us about naming our arguments:
The interpretation of the unnamed arguments of seq and seq.int is not standard, and it is recommended always to name the arguments when programming.
Problem
I like to use the `seq()` command in R to create a sequence starting at zero. but when I type e.g. ``` seq(0:14) ``` I get the following output: ``` 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 ``` What am I doing wrong?