python time offset
python, time
Solution
Use a `datetime.datetime()`, then add or subtract `datetime.timedelta()` instances.
>>> import datetime
>>> t = datetime.datetime.now()
>>> t - datetime.timedelta(hours=1, minutes=10)
datetime.datetime(2012, 12, 26, 17, 18, 52, 167840)
`timedelta()` arithmetic is not supported for `datetime.time()` objects; if you need to use offsets from an existing `datetime.time()` object, just use `datetime.datetime.combine()` to form a `datetime.datetime()` instance, do your calculations, and 'extract' the time again with the `.time()` method:
>>> t = datetime.time(1, 2)
>>> dt = datetime.datetime.combine(datetime.date.today(), t)
>>> dt
datetime.datetime(2012, 12, 26, 1, 2)
>>> dt -= datetime.timedelta(hours=5)
>>> dt.time()
datetime.time(20, 2)
Problem
How can I apply an offset on the current time in python? In other terms, be able to get the current time minus x hours and/or minus m minutes and/or minus s secondes and/or minus ms milliseconds for instance ``` curent time = 18:26:00.000 offset = 01:10:00.000 =>resulting time = 17:16:00.000 ```