How to use typeid to store a type_info object
c++
Solution
`typeid()` returns a `const type_info &` and `type_info` has a private copy constructor, so you can't build the array you describe. I can't find anything to say whether they are persistent, but you could try `type_info *a[] = { &typeid(int), ... }`
Problem
I am trying to create and store a type_info object: ``` #include <typeinfo> int i; type_info x = typeid(i); ``` And an error message is generated. Is there any way to store a type_info object? The history behind this is that I am trying to generate test cases for various C++ integer types; doing arithmetic on them and determining whether intermediate results are promoted to the next largest integer type or truncated. That is: ``` unsigned char x = 257; unsigned char y = 257; // is (x + y) == 514 or 256? ``` And decided to do a type check against a static data structure, for example: ``` int x = <value>; int y = <value>; static type_info def = { typeid(bool) , typeid(char), typeid(unsigned char) , typeid(short), typeid(unsigned short) , typeid(long), typeid(unsigned long) }; type_info obj = typeid(x + y); for(int i = 0; i < sizeof(def)/sizeof(def[0]); i++) if (obj == def[i]); break; ``` Anyhow, it can't be done without being able to store the type_info structure and I would still like to find out about integer promotions. Can you create a type_info object? The gcc 4.5.3 implementation has assignment as private. Is there a resource telling when integer promotions are performed? thanks