Getting the z-index of a DIV in JavaScript?

Question

I have a div `normaldiv1` with class `normaldiv`. I am trying to access its z-index through the style property but it always returns 0 although it's set to 2 in the stylesheet. CSS: ``` .normaldiv { width:120px; height:50px; background-color:Green; position: absolute; left: 25px; top:20px; display:block; z-index:2; } ``` ` HTML: ```

``` JavaScript: ``` alert(document.getElementById('normaldiv1').style.zIndex); ``` How can I find the z-index of an element using JavaScript?

Accepted Answer

Since z index is mentioned in the CSS part you won't be able to get it directly through the code that you have mentioned. You can use the following example.

```
function getStyle(el,styleProp)
{
    var x = document.getElementById(el);

if (window.getComputedStyle)
    {
        var y = document.defaultView.getComputedStyle(x,null).getPropertyValue(styleProp); 
    }  
    else if (x.currentStyle)
    {
        var y = x.currentStyle[styleProp];
    }

return y;
}
```

pass your element id and style attribute to get to the function.

Eg:

```
var zInd = getStyle ( "normaldiv1" , "zIndex" );
alert ( zInd );
```

For firefox you have to pass z-index instead of zIndex

```
var zInd = getStyle ( "normaldiv1" , "z-index" );
 alert ( zInd );
```

Reference

Getting the z-index of a DIV in JavaScript?

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