How are booleans "notted" in assembly?

I understand that in C-like languages I can perform a boolean not with the `not` operator: (C) ``` int myBool = TRUE; myBool = !myBool; ``` But my question is: How is this implemented behind the scenes? My guess is by using jumps, but those could be inefficient if used excessively: (Intel x86 syntax) ``` ; assume eax holds boolean test eax, eax jnz short boolTrue inc eax ; eax was 0, now 1 jmp short after boolTrue: ; eax non-zero xor eax, eax ; eax now 0 after: ``` As shown, it requires 5 instructions with at least one jump and one bit-wise `and` (`test`). There has to be an easier way to do this because I've seen code bases that do "double-nots" (`if (!!fileHandle)`) for some weird reason. So (as said above): How do compilers do boolean `!`s on x86?