Regex, get what's after the second occurence of a string

find, regex, string

Solution

The regex `(?:.*?####){2}(.*)` contains what you're looking for in its first group.

Problem

I have a string of the following format: `TEXT####TEXT####SPECIALTEXT` I need to get the `SPECIALTEXT`, basically what is after the second occurrence of the `####`. I can't get it done. Thanks

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