Accidental expression evaluation in ruby
expression, ruby, ruby-on-rails
Solution
Ruby allows you to use `_` to break up long numbers, for example
123456789 == 123_456_789
but the latter is a little easier to read, so your code is the same as `12.next`
Problem
Why this expression evaluating to 13 ?. I accidentally evaluated this expression `(1_2).next` instead of `(1+2).next` which o/p 4 as result. ``` => (1_2).next => 13 ``` Please let me know how this is, as i m new to Ruby