Sorting an array of strings in reverse alphabetical order in Java

Question

I've been tasked with turning this code into a reverse sort, but for the life of me cannot figure out how to do it. These are my sort, findlargest and swap methods. I have a feeling I am missing something glaringly obvious here, any help would be really appreciated. ``` public static void sort(String[] arr) { for (int pass = 1; pass < arr.length; pass++) { int largestPos = findLargest(arr, arr.length - pass); if (largestPos != arr.length - pass) { swap(arr, largestPos, arr.length - pass); } } } public static int findLargest(String[] arr, int num) { int largestPos = 0; for (int i = 1; i <= num; i++) { if (arr[i].compareToIgnoreCase(arr[largestPos]) > 0) { largestPos = i; } } return largestPos; } public static void swap(String[] arr, int first, int second) { String temp = arr[first]; arr[first] = arr[second]; arr[second] = temp; } } ```

Accepted Answer

Don't reinvent the wheel -

```
String[] strs = {"a", "b", "d", "c", "e"};

Arrays.sort(strs, Collections.reverseOrder(String.CASE_INSENSITIVE_ORDER));

System.out.println(Arrays.toString(strs));
```

```
[e, d, c, b, a]
```

Sorting an array of strings in reverse alphabetical order in Java

Solution

Problem