C++ Function Type?

Question

I'm new to, and learning C++ (know a lot of Java) and the following code confuses me... I know this code fragment is dealing with a pointer-to-function (it's a callback, that makes sense) but what is throwing me off is the argument between the return type and the function name. What the bloody hell is that? It looks like a type of function, but I have never heard of that and even after searching and reading about pointer-to-functions I was not able to find anything mentioning that functions could have a type. If this is true, how does one define a function type? Thanks, -Cody

Accepted Answer

`GLFWCALL` is not a type, it's a macro which is expanded to a calling convention specific to the platform, or an empty string. Here's a trimmed fragment of glfw.h:

```
#if defined(_WIN32) && defined(GLFW_BUILD_DLL)
 #define GLFWCALL     __stdcall
#elif defined(_WIN32) && defined(GLFW_DLL)
 #define GLFWCALL     __stdcall
#else
 /* We are either building/calling a static lib or we are non-win32 */
 #define GLFWCALL
#endif
```

Using a correct calling convention is important on x86/win32, since some of them expect the stack to be cleaned by callee and others by the caller. There can also be differences in the order of passing the arguments.

C++ Function Type?

Solution

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