What's the use of memset() return value?
c, c++, memset
Solution
The signature is in line with all the other similar functions: `memcpy()`, `strcpy()` etc. I always thought this was done to enable one to chain calls to such functions, and to otherwise use such calls in expressions.
That said, I've never come across a real-world situation where I would feel compelled to use the return value in such a manner.
Problem
`memset()` is declared to return `void*` that is always the same value as the address passed into the function. What's the use of the return value? Why does it not return `void`?