Remove duplicates in Django ORM -- multiple rows

django, django-models

Solution

def remove_duplicated_records(model, fields):
    """
    Removes records from `model` duplicated on `fields`
    while leaving the most recent one (biggest `id`).
    """
    duplicates = model.objects.values(*fields)

    # override any model specific ordering (for `.annotate()`)
    duplicates = duplicates.order_by()

    # group by same values of `fields`; count how many rows are the same
    duplicates = duplicates.annotate(
        max_id=models.Max("id"), count_id=models.Count("id")
    )

    # leave out only the ones which are actually duplicated
    duplicates = duplicates.filter(count_id__gt=1)

    for duplicate in duplicates:
        to_delete = model.objects.filter(**{x: duplicate[x] for x in fields})

        # leave out the latest duplicated record
        # you can use `Min` if you wish to leave out the first record
        to_delete = to_delete.exclude(id=duplicate["max_id"])

        to_delete.delete()

You shouldn't do it often. Use `unique_together` constraints on database instead.

This leaves the record with the biggest `id` in the DB. If you want to keep the original record (first one), modify the code a bit with `models.Min`. You can also use completely different field, like creation date or something.

Underlying SQL

When annotating django ORM uses `GROUP BY` statement on all model fields used in the query. Thus the use of `.values()` method. `GROUP BY` will group all records having those values identical. The duplicated ones (more than one `id` for `unique_fields`) are later filtered out in `HAVING` statement generated by `.filter()` on annotated `QuerySet`.

SELECT
    field_1,
    …
    field_n,
    MAX(id) as max_id,
    COUNT(id) as count_id
FROM
    app_mymodel
GROUP BY
    field_1,
    …
    field_n
HAVING
    count_id > 1

The duplicated records are later deleted in the `for` loop with an exception to the most frequent one for each group.

Empty .order_by()

Just to be sure, it's always wise to add an empty `.order_by()` call before aggregating a `QuerySet`.

The fields used for ordering the `QuerySet` are also included in `GROUP BY` statement. Empty `.order_by()` overrides columns declared in model's `Meta` and in result they're not included in the SQL query (e.g. default sorting by date can ruin the results).

You might not need to override it at the current moment, but someone might add default ordering later and therefore ruin your precious delete-duplicates code not even knowing that. Yes, I'm sure you have 100% test coverage…

Just add empty `.order_by()` to be safe. ;-)

https://docs.djangoproject.com/en/3.2/topics/db/aggregation/#interaction-with-default-ordering-or-order-by

Transaction

Of course you should consider doing it all in a single transaction.

https://docs.djangoproject.com/en/3.2/topics/db/transactions/#django.db.transaction.atomic

Problem

I have a model that has four fields. How do I remove duplicate objects from my database? Daniel Roseman's answer to this question seems appropriate, but I'm not sure how to extend this to situation where there are four fields to compare per object. Thanks, W.

Original source

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