How to get fields with same name as class parameters in Scala?
case-class, scala
Solution
You just need to add `val` to turn your parameters into public fields of your class:
class Person(val name: String, val age: Int)
^^^ ^^^
Case classes, as you noticed, do this by default.
Problem
Take a simple class like the following: ``` class Person(name: String, age: Int) {} ``` Now, when I instantiate this class, I typically want its users to be able to use `name` and `age`. Like: ``` val ronald = new Person("Ronald", 22) val ronaldsName = ronald.name // <- ``` This doesn't work of course unless I either define a getter called `name`, or make `Person` a case class. The latter is an easy solution, but I sort of feel like I'm abusing case classes? Still the former is kind of a little inconvenient since I can't simply: ``` class Person(name: String, age: Int) { def name = name } ``` So, then I would have to rename the first `name` in the class's constructor to something else, like `personName` or `_name` or `n`. But that is sort-of confusing and far less elegant in my eyes. It's the same concept/variable/value, so it should have the exact same name, right? So ... what is the best or correct practice here? It's so tempting to just add that `case`.